Question

http://prntscr.com/d1fbj8 @3mar

Answer 1

How do I solve this?

Answer 2

This is the general case where we need to use the general formula for the distance between points.

Apply this to two consecutive points twice. and tell me the steps and the naswer as you did before!

Thanks in advance.

Answer 3

Oh okay! One second

Answer 4

OOKK

Answer 5

Thank you for the medal!

Answer 6

Do I use these points?

Answer 7

Yes.
and your answer is ??

Answer 8

I got 10.1

Answer 9

@3mar

Answer 10

For that length or perimeter?

Answer 11

Im not sure.. this is how I solved it though.
√(-7-3)^2+(4-2)^2
√(-10)^2+(2)^2
√100+4
√104
√10.1

Answer 12

Ok that is one side.
for the adjacent side, what you got?

Answer 13

11.1

Answer 14

√104 =√10.1???

Answer 15

I think √104=10.198

Answer 16

oh I thought you meant do the bottom points of the rectangle.

Answer 17

These are your steps:
"Im not sure.. this is how I solved it though. √(-7-3)^2+(4-2)^2 √(-10)^2+(2)^2 √100+4 √104 √10.1"

Answer 18

yes

Answer 19

ok
what is the perimeter therefore?

Answer 20

10.1?

Answer 21

no, I think the perimeter would be \[6\sqrt26=30.59\]

Answer 22

10.1? is not in the choices!

Answer 23

20.4?

Answer 24

30.59

Answer 25

so 30.6 would be the answer

Answer 26

yes. Satisfied?

Answer 27

Can you write all the steps of how you got 30.59 so I can write them down in my notes? Please

Answer 28

Of course.

Answer 29

Thank you :)

Answer 30

For L (the length):
\[L=\sqrt{(4-2)^2+(-6-4)^2}=\sqrt{104}=2\sqrt{26}\]

For d (the width):
\[d=\sqrt{(-3-2)^2+(3-4)^2}=\sqrt{26}=\sqrt{26}\]

The perimeter is twice the sum of the length and width

\[The.perimeter=2*[2\sqrt{26}+\sqrt{26}]=6\sqrt{26}=30.59\]

I hope that helps!

Answer 31

The mistake you did is the point you chose not correct!

It would be (4,2) rather than (3,2)

Answer 32

Oh okay thanks so much

Answer 33

With my pleasure!

Answer 34

I thank you that you gave me that chance to help you!