Question

look!

Answer 1

@3mar

Answer 2

@563blackghost

Answer 3

Hello! ghost!

Answer 4

Heyo :)

Answer 5

you're a mathlete congrats!!!

Answer 6

Oh thank you :)

Answer 7

@mathmate

Answer 8

I think the answer is A

Answer 9

\[-30<c<130\]
\[Replace ~c~by~\frac{ 5 }{ 9 }\left( F-32 \right)\]
and then solve for F

Answer 10

what do you mean replace C by 5 over 9

Answer 11

for this first multiply each inequality by 9

Answer 12

An easy way is to do the inverse transformation.
C=5/9*(F-32)
multiply both sides by 9/5
(9/5)C=F-32
F=32+(9/5)C

Example for the first option:
C=-30
F=32+(9/5)(-30)=32-54=-22 which matches the second inequality.
So continue this way to find the right answer.

Answer 13

then divide each by 5

Answer 14

and do the same for 130

Answer 15

Lastly add 32 to each

Answer 16

what??

Answer 17

how did we get 9/5C + 32 when it was - 32

Answer 18

-270<5(F-32)<1170
divide by 5
-54<F-32<234
add 32 to each
-22<F<266

Answer 19

5(f-32) ???

Answer 20

you mean 9/5 ?

Answer 21

see my first posting ,then step by step

Answer 22

im soooo confused

Answer 23

what an inequality

Answer 24

formula for converting centigrade to Fahrenheit is

\[c=\frac{ 5 }{ 9 }\left( F-32 \right)\]

Answer 25

in the statement it is given c lies between -30 and 130

Answer 26

okay

Answer 27

how do we get (9/5)C=F-32
F=32+(9/5)C

Answer 28

how was is it minus and know its addition??

Answer 29

whattt how do you get -270?!?!??!?!?!

Answer 30

agent can we start from beginning

Answer 31

\[-30<C<130\]
\[-30<\frac{ 5 }{ 9 }\left( F-32 \right)<130\]
multiply by 9
\[-30 \times 9<9 \times \frac{ 5 }{ 9 }\left( F-32 \right)<9 \times 130\]
\[-270<5\left( F-32 \right)<1170\]
divide each by 5
\[\frac{ -270 }{ 5 }<\frac{ 5(F-32) }{ 5 }<\frac{ 1170 }{ 5 }\]
\[-54<F-32<234\]
add 32 to each
-54+32<F-32+32<234+32
-22<F<266

Answer 32

o

Answer 33

i understand