Question

I need some help, I don't just want the answer, I want to figure this out. It's a simple trigonometric function set up, it is attached in comments.

Answer 1

If I may help?

Answer 2

PLEASE

Answer 3

Thank you.

Answer 4

Can you represent the theta on a right triangle?

Answer 5

I'm not sure,

Answer 6

I think I'm suppose to take and divide (5/3) by sec to isolate theta

Answer 7

What sec represents?

Answer 8

Secant is the reciprocal of cosine, sec = 1/cos

Answer 9

\[\sec \theta=\frac{ 1 }{ \cos \theta }=\frac{ hyp }{ adj }\]

Answer 10

So if sec = 5/3, then I would undo the reciprocal to get 3/5, giving me the hypotenuse and adjacent?