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A particle moves along the x-axis so that at any time t>=0 its velocity is given by v(t)=cos(2-t^2). The position of the particle is 3 at time t=0. What is the position of the particle when its velocity is first equal to 0?
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p(t) = ∫ v(t)
ahh okay thank you. I would use the chain rule for this right..?
U substitution
remember to add the position at zero after anti deriving
wait what does it mean by what is the position when velocity is first equal to 0 ?
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You find the zeros of v(t) and using that t you plug it into p(t)
ah okay thanks again
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