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Mathematics 8 Online
OpenStudy (thatonegirl_):

A particle moves along the x-axis so that at any time t>=0 its velocity is given by v(t)=cos(2-t^2). The position of the particle is 3 at time t=0. What is the position of the particle when its velocity is first equal to 0?

OpenStudy (issimplcalcus):

p(t) = ∫ v(t)

OpenStudy (thatonegirl_):

ahh okay thank you. I would use the chain rule for this right..?

OpenStudy (issimplcalcus):

U substitution

OpenStudy (issimplcalcus):

remember to add the position at zero after anti deriving

OpenStudy (thatonegirl_):

wait what does it mean by what is the position when velocity is first equal to 0 ?

OpenStudy (issimplcalcus):

You find the zeros of v(t) and using that t you plug it into p(t)

OpenStudy (thatonegirl_):

ah okay thanks again

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