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Mathematics 20 Online
OpenStudy (pflori1234_pop):

hey can someone help me with 8 math questions on parabola? THANK YOU SO MUCH

OpenStudy (pflori1234_pop):

OpenStudy (pflori1234_pop):

@DanJS can u help?

OpenStudy (danjs):

yeah, it looks like they want you to put each one in the form at the top...

OpenStudy (pflori1234_pop):

ya

OpenStudy (danjs):

-2x^2 = 16y put that into the form at the top

OpenStudy (pflori1234_pop):

i kinda need help

OpenStudy (pflori1234_pop):

@zepdrix @triciaal

OpenStudy (danjs):

do you want to know how that equation is made, where it comes from, or just how to use it ?

OpenStudy (danjs):

To just use the thing, solve the problem for y first -2x^2=16y \[\large y=\frac{ -1 }{ 8 }x^2\] look at the form of the equation.. \[\large y=\frac{ 1 }{ 4p }(x-h)^2+k\] vertex- (h,k) focus - (h, k+p) directrix- y=k-p

OpenStudy (danjs):

if you want you can fill in the zeros to make it look the same \[y=\frac{ -1 }{ 8 }(x-0)^2+0\]

OpenStudy (danjs):

Reading from the equation, the -1/8 is the same as the 1/(4p), so \[\frac{ -1 }{ 8 }=\frac{ 1 }{ 4p }\] p=-2

OpenStudy (danjs):

Then just read the values from the equation.. vertex (h,k) = (0,0) focus (h,k+p) = (0,-2) directrix - (h, k-p) = (0,2)

OpenStudy (danjs):

I would find the x and y axis intercepts (0,y), (x,0) to use for points to graph, then also the vertex point. Here only intercepts are (0,0). |dw:1478144068529:dw|

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