Question

Kevin has $4.85 in nickels and dimes. If he has 34 fewer dimes than nickels, how many coins (nickels and dimes) does he have altogether?
74 coins
75 coins
76 coins
77 coins

Answer 1

@bonnieisflash1.0

Answer 2

76 coins

Answer 3

u sure???

Answer 4

here is a method Set the 34 more nickels aside.
--> pairs of 1n & 1d each worth 15 cents & a total of $3.15 ($4.85 - $1.70)
315/15 = 21 pairs
--> 21 dimes and 55 nickels

Answer 5

Kevin has $4.85 in nickels and dimes. If he has 34 fewer dimes than nickels, how many coins (nickels and dimes) does he have altogether?
------------
n = d + 34
5n + 10d = 485

Answer 6

another method:
Set the 34 more nickels aside.
--> pairs of 1n & 1d each worth 15 cents & a total of $3.15 ($4.85 - $1.70)
315/15 = 21 pairs
--> 21 dimes and 55 nickels