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Mathematics 16 Online
OpenStudy (lord2clash):

Select the two values of x that are roots of the given polynomial below. 2x^2 + 11x + 15

OpenStudy (lord2clash):

OpenStudy (welshfella):

you can either solve the equaton or plug in the given roots and see which fit.

OpenStudy (welshfella):

it will b easier to solve. Suggest you Use the quadratic formula

OpenStudy (welshfella):

or do you think you can factor it? Have you heard of the ac method of factoring these equations?

OpenStudy (lord2clash):

no i have not...

OpenStudy (welshfella):

Ok then how about the quadratic formula?

OpenStudy (lord2clash):

i think this is it? a x 2 + b x + c = 0

OpenStudy (welshfella):

No that is the general form of the equation quadratic formula is x = [-b +/- sqrt(b^2 - 4ac) ] / 2a

OpenStudy (lord2clash):

oh okay

OpenStudy (welshfella):

so plug in the values of a b and c

OpenStudy (welshfella):

and youll get the roots.

OpenStudy (lord2clash):

x = [-11x +/- sqrt(11x^2 - 4a15) ] / 2a (is that right?)

OpenStudy (welshfella):

no you dont include the x a = 2 , b = 11 and c = 15

OpenStudy (lord2clash):

x = [-11 +/- sqrt(11^2 - 4*2*15) ] / 2*2 (idk if im supposed to put ^ between a c or *)

OpenStudy (welshfella):

* is correct Multiply Thats corrrect

OpenStudy (welshfella):

can you work it out?

OpenStudy (lord2clash):

when i did it all i got 10... idk if thats right or not.... i really suck at these problems

OpenStudy (welshfella):

x = [-11 +/ - sqrt(121- 120)] / 4 = (-11 + 1] / 4 or (-11 - 1) / 4

OpenStudy (jtm-pa):

-3 and -5/2

OpenStudy (welshfella):

right

OpenStudy (lord2clash):

-5/2 isnt an option ... but -2.5 is

OpenStudy (lord2clash):

OpenStudy (jtm-pa):

It is D and E ...

OpenStudy (welshfella):

-5/2 is the same as -2.5

OpenStudy (jtm-pa):

exactly...

OpenStudy (lord2clash):

Oh okay thank you both cx

OpenStudy (welshfella):

yw

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