Mathematics
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OpenStudy (lord2clash):
Select the two values of x that are roots of the given polynomial below.
2x^2 + 11x + 15
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OpenStudy (lord2clash):
OpenStudy (welshfella):
you can either solve the equaton or plug in the given roots and see which fit.
OpenStudy (welshfella):
it will b easier to solve.
Suggest you Use the quadratic formula
OpenStudy (welshfella):
or do you think you can factor it?
Have you heard of the ac method of factoring these equations?
OpenStudy (lord2clash):
no i have not...
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OpenStudy (welshfella):
Ok then how about the quadratic formula?
OpenStudy (lord2clash):
i think this is it? a x 2 + b x + c = 0
OpenStudy (welshfella):
No that is the general form of the equation
quadratic formula is x = [-b +/- sqrt(b^2 - 4ac) ] / 2a
OpenStudy (lord2clash):
oh okay
OpenStudy (welshfella):
so plug in the values of a b and c
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OpenStudy (welshfella):
and youll get the roots.
OpenStudy (lord2clash):
x = [-11x +/- sqrt(11x^2 - 4a15) ] / 2a (is that right?)
OpenStudy (welshfella):
no you dont include the x
a = 2 , b = 11 and c = 15
OpenStudy (lord2clash):
x = [-11 +/- sqrt(11^2 - 4*2*15) ] / 2*2 (idk if im supposed to put ^ between a c or *)
OpenStudy (welshfella):
* is correct Multiply
Thats corrrect
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OpenStudy (welshfella):
can you work it out?
OpenStudy (lord2clash):
when i did it all i got 10... idk if thats right or not.... i really suck at these problems
OpenStudy (welshfella):
x = [-11 +/ - sqrt(121- 120)] / 4
= (-11 + 1] / 4 or (-11 - 1) / 4
OpenStudy (jtm-pa):
-3 and -5/2
OpenStudy (welshfella):
right
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OpenStudy (lord2clash):
-5/2 isnt an option ... but -2.5 is
OpenStudy (lord2clash):
OpenStudy (jtm-pa):
It is D and E ...
OpenStudy (welshfella):
-5/2 is the same as -2.5
OpenStudy (jtm-pa):
exactly...
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OpenStudy (lord2clash):
Oh okay thank you both cx
OpenStudy (welshfella):
yw