help please
So first I would change it into slope intercept form to make it easier to deal with\[y=mx+b\]
ok
Once you have it in slope intercept insert the points into a point slope form which is \[y-y _{1}=m(x-x _{1})\]. Then insert the x and y coordinates into the x1 and y1
Just message me when you are done! :)
12
or -12
You should come out with an equation
oh, 0 -0^1=4(4-4^1)
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oh....so the answer is 3/4?
No that was putting the original equation, which was in standard form, into slope intercept. Now we have to do point slope
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Now you need to simplify it so that
Were you able to simplify it?
no...
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That should be your answer. I dont know if you have to have it standard form, so if you have to change it back. Any questions?
wait so the answer is 3/4x -3?
yeah it should be y=3/4x-3
So that would be the equation that is parallel to the original with those coordinates.
i dont have any graph tools....
an easier way would be to say that since these lines are parallel, their difference can only be the y intercept, because parallel means slope is the same. Remeber that a line contants two constants, one for slope, one for y-intercept. If their slope is the same, y-intercept has to be different otherwise two lines are the same
therefore we can immediately say that we have an equation of the form\[-3x+4y=b\]
now, let x=4 and y-0, you get b=-12
so -12 is the anser.
no, the answer is -3x+4y=-12, the whole eqn is the answer
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