Question

Solve the following equation for x
2^7-x * 2^5+4x = 64

Answer 1

You can rewrite 64 as 2^6 and cancel the 2s
7-x +5+4x=6
3x=6-12
x=-6/3
x=-2

Answer 2

But doesn't it say x * 2^5?

Answer 3

128 - x(32) + 4x = 64.
128 - 28x = 64.
-28x = 64.
x = -2.29

Answer 4

I did as 2^(7-x) * 2^(5-4x) = 64

Answer 5

But you didn't multiple them?

Answer 6

2^7-x * 2^5+4x = 64
7 - x * 5 + 4x = 6
7 - 5x + 4x = 6.
7 - x = 6.
x = 1.

Answer 7

If it was written more clearly, maybe we could have a definite answer.

Answer 8

When you have like 2^2 * 2^3 you sum the powers

Answer 9

I never said you were wrong, just not clearly written well enough.

Answer 10

Thank you so much @Styxer