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OpenStudy (laviajmani):
Solve the following equation for x e^(3x^2 - 14x) = e^5
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OpenStudy (styxer):
You can cancel out the "e" and just calculate (3x^2-14x)=5 , it will result in bhaskara 3x^2-14x-5=0 x can be either -1/3 or 5
OpenStudy (sweetburger):
Yes considering both sides of the equation have the same base you can say \[3x^2-14x=5\]
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