Question

Solve the following equation for x
e^(3x^2 - 14x) = e^5

Answer 1

You can cancel out the "e" and just calculate (3x^2-14x)=5 , it will result in bhaskara
3x^2-14x-5=0
x can be either -1/3 or 5

Answer 2

http://www.wolframalpha.com/input/?i=e%5E(3x%5E2+-+14x)+%3D+e%5E5

Answer 3

Yes considering both sides of the equation have the same base you can say
\[3x^2-14x=5\]