Question

https://gyazo.com/956513ed6f35527d4b460dc3a485c301

Answer 1

im confused

Answer 2

\[\large 5x+2y=2\]\[\large 5(0)+2y=2\]\[\large 2y=2\]\[\large y =1\]
5 x + 2y = 2 will have a y intercept of 1.

Answer 3

the question is asking which option will have a value of y = 1 when x = 0?

Answer 4

Yes, you simply plug in 0 for x and see if y = 1.

Answer 5

how do i plug in

Answer 6

All you have to do is cancel out the x-terms, as you saw in my example.

Answer 7

2x + 5y = 8
2(0) + 5y = 8
5y = 8
how did u get the last one

Answer 8

2y=2
y=1

Answer 9

5y = 8
y = 8/5
So the above equation would have a y intercept at 8/5, which is clearly not 1.

Answer 10

ohh okay. ty

Answer 11

5x + 2y = 2
5(0) + 2y = 2
2y = 2
1

Answer 12

so thats the eanswer?

Answer 13

Yup, that is right!

Answer 14

thanks guys