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Mathematics 14 Online
OpenStudy (sleepyjess):

Need to find the limit of the below function using L’Hôpital’s Rule http://prntscr.com/d4045x

OpenStudy (sleepyjess):

I missed the lesson on Friday due to a diving competition and I'm not even sure what the rule is

OpenStudy (steve816):

Hey there, all you have to do is differentiate the numerator and the denominator.

OpenStudy (sleepyjess):

That's all there is to it? So \(\dfrac{20x^3-8x}{27x^2+1}\)? What do I do from there? Just plug in numbers to find the limit?

OpenStudy (steve816):

Yup! And if you plug in 1, you will get a value! What would that be?

OpenStudy (sleepyjess):

3/7

OpenStudy (sleepyjess):

Could I ask another quick question? How do you differentiate \(e^{2x}\)?

OpenStudy (steve816):

Great work :D 3/7 is correct. |dw:1478480965554:dw|

OpenStudy (loser66):

hahahahahaha..................

OpenStudy (steve816):

To differentiate e^2x, you must use the chain rule.

OpenStudy (sleepyjess):

2e^2x?

OpenStudy (steve816):

Yup, that is the derivative of e^2x !!

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