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Need to find the limit of the below function using L’Hôpital’s Rule http://prntscr.com/d4045x
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I missed the lesson on Friday due to a diving competition and I'm not even sure what the rule is
Hey there, all you have to do is differentiate the numerator and the denominator.
That's all there is to it? So \(\dfrac{20x^3-8x}{27x^2+1}\)? What do I do from there? Just plug in numbers to find the limit?
Yup! And if you plug in 1, you will get a value! What would that be?
3/7
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Could I ask another quick question? How do you differentiate \(e^{2x}\)?
Great work :D 3/7 is correct. |dw:1478480965554:dw|
hahahahahaha..................
To differentiate e^2x, you must use the chain rule.
2e^2x?
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Yup, that is the derivative of e^2x !!
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