Question

Three consecutive integers have a sum of 87. Find the integers.

Answer 1

Any ideas?

Answer 2

Heyyy let's do some fun math! If three consecutive integers have a sum of 87, it would look like\[\huge x + (x + 1) + (x + 2) = 87\]
Do you think you can solve for x?

Answer 3

I just sort of started somewhere and worked from there. I didn't even think in terms of a formula :/ Pick three numbers that are consecutive and add them together.

Answer 4

28

Answer 5

thats what i got for x

Answer 6

Perfect, now plug in what you got for x into the binomials and you'll get the integers :)

Answer 7

Does that make sense? @steve816 did a great job with that equation

Answer 8

That is correct! Now as @taliam15 said, plug in 28 for x to get the 3 values!

Answer 9

Welcome to OpenStudy @taliam15 !!!

Answer 10

Thank you :)

Answer 11

@Ebonyserrano did we help at all?

Answer 12

yes

Answer 13

thank you guys

Answer 14

okay good :D and no problem glad I could finally assist someone in some way on here lol

Answer 15

i just got 87

Answer 16

so is it 28, 87, and 87?

Answer 17

Actually, it would be 28, 29, and 30.

Answer 18

oh, no. Okay so you're going to plug in 28 for each value of x, even the ones in the parenthesis.

Answer 19

i did

Answer 20

yeah, and when you do that you get what he said ^

Answer 21

ok thanks

Answer 22

You sure you got it?

Answer 23

can you guys help me with two more?

Answer 24

I can show you

Answer 25

\[\left( 28 \right)\left( 28 + 1 \right)\left( 28+2) \right)\]

Answer 26

28 + 29 + 30 = 87

Answer 27

oh darn I have somewhere to go for about an hour if you wanna hold out I'll help but maybe @steve816 could help, sorry

Answer 28

ok thanks