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Mathematics 16 Online
OpenStudy (julyahx1):

A pool company is creating an image for a client that has the look of a 3-D image for a family pool and a similar dog pool. Find the value of c in the drawing below: Quadrilaterals LMNO and PQRS are shown. Side LM measures 4, side MN measures 6, side NO measures a, side OL measures 7, side PQ measures 2, side QR measures c, side RS measures 5, side SP measures b. Numerical Answers Expected! Answer for Blank 1:

OpenStudy (julyahx1):

OpenStudy (julyahx1):

An architect planned to construct two similar stone pyramid structures in a park. The figure below shows the front view of the pyramids in her plan, but there is an error in the dimensions: Two similar scalene triangles PQR and ABC with angle P congruent to angle A, angle Q congruent to angle B, and QR and BC as the bases of the triangles. The length of PQ is 9 feet, the length of QR is 10.5 feet, and the length of RP is 7.5 feet. The length of AB is 6 feet, the length of BC is 7 feet, and the length of CA is 4.5 feet. Which of the following changes should she make to the length of side CA to correct her error? Change the length of side CA to 6 feet Change the length of side CA to 3 feet Change the length of side CA to 5 feet Change the length of side CA to 8 feet

OpenStudy (julyahx1):

OpenStudy (julyahx1):

those are it

OpenStudy (sooobored):

ok the thing about similar shapes, is that the sides are proportional to each other

OpenStudy (sooobored):

as long as you are comparing a side to the corresponding side

OpenStudy (julyahx1):

ok

OpenStudy (sooobored):

so side LM is proprotional to side PQ

OpenStudy (julyahx1):

and side O N is proportional so sides SR

OpenStudy (julyahx1):

ON*

OpenStudy (sooobored):

we want to find c which is the side QR, which side is proportional to it?

OpenStudy (julyahx1):

6 on side MN

OpenStudy (sooobored):

ok, i cant really think of the steps leading up to this, but the proportion of ML- QP must be equal to the proportion MN-QR

OpenStudy (sooobored):

if you've ever learned ratios or remember it, we can write the propertion ML-QP as \[\frac{4}{2}\]

OpenStudy (sooobored):

and that is equal to the proportion MN-QR so \[\frac{4}{2}= \frac{6}{c}\]

OpenStudy (julyahx1):

and the other as 6 over c?

OpenStudy (sooobored):

and then you can solve for c, but it should be really obvious by looking at it

OpenStudy (julyahx1):

yeah u just did it lol

OpenStudy (sooobored):

c=?

OpenStudy (julyahx1):

im not so sure yikes..

OpenStudy (julyahx1):

2

OpenStudy (julyahx1):

or 4

OpenStudy (sooobored):

4/2 is 2, yes so 6 divided by what is equal to 2?

OpenStudy (julyahx1):

3

OpenStudy (sooobored):

here let me changes the proportion around if it helps \[\frac{2}{4}=\frac{c}{6}\]

OpenStudy (sooobored):

thats the same thing, and yes c = 3

OpenStudy (sooobored):

any questions about it?

OpenStudy (julyahx1):

oh great so the answer is 3? and no i got it thanks so much (:

OpenStudy (sooobored):

ok, moving onnnn

OpenStudy (sooobored):

the problem states, we have 2 similar triangles

OpenStudy (julyahx1):

yupp last one yay lmao

OpenStudy (sooobored):

if you remember what similar triangles mean, the triangles share the same corresponding angles, so angle B=Q R=C, etc

OpenStudy (julyahx1):

yes

OpenStudy (sooobored):

now, the problem states, there is a problem with side length CA

OpenStudy (sooobored):

so we completely ignore the 4.5ft, and assume its a side length of "x"

OpenStudy (julyahx1):

ok

OpenStudy (sooobored):

now, remember what we did with the last problem, for similar shapes, that means the corresponding sides are proportional to each other

OpenStudy (sooobored):

so what side is CA proportional to?

OpenStudy (julyahx1):

riight like we just did with the division

OpenStudy (julyahx1):

RQ

OpenStudy (sooobored):

wrong

OpenStudy (julyahx1):

nooo

OpenStudy (julyahx1):

mistake sorry

OpenStudy (julyahx1):

i mean RP

OpenStudy (julyahx1):

RP

OpenStudy (sooobored):

yes

OpenStudy (julyahx1):

so 4.5 ft is proportional to 7.5 ft

OpenStudy (sooobored):

ok, if we want to put it interms of a fraction its \[\frac{x}{7.5}\]

OpenStudy (sooobored):

no, remember the problem said 4.5 is wrong

OpenStudy (julyahx1):

oh right i forgot its X

OpenStudy (sooobored):

ok, now we want to look at a known proportion, it might be BC-QR or AB-PQ

OpenStudy (sooobored):

pick one of them

OpenStudy (julyahx1):

bc qr

OpenStudy (sooobored):

so the ratio between the two are?

OpenStudy (julyahx1):

10.5 and 7.0

OpenStudy (sooobored):

7.0 and 10.5, respectively since we wrote it as BC- QR

OpenStudy (sooobored):

now if we compare the 2 ratios to each other, it might look something like \[\frac{x}{7.5}=\frac{7}{10.5}\]

OpenStudy (sooobored):

and now we solve for x which is side length CA

OpenStudy (sooobored):

and the answer isssss?

OpenStudy (sooobored):

its ok to grab a calculator for this

OpenStudy (sooobored):

but, for equations, what you want to do is multiple 7.5 to both sides

OpenStudy (julyahx1):

ya i need a calculator for this i lost mine so i have to find one on google

OpenStudy (julyahx1):

should i look for like a geometry calculator?

OpenStudy (sooobored):

dosent matter, a basic calculator will work

OpenStudy (julyahx1):

ok

OpenStudy (sooobored):

\[7.5*\frac{x}{7.5}=7.5*\frac{7}{10.5}\] \[x=7.5*\frac{7}{10.5}\]

OpenStudy (sooobored):

your computer should have a calculator

OpenStudy (julyahx1):

but u can't write x on it

OpenStudy (sooobored):

we're solving for x you dont need to write x

OpenStudy (sooobored):

you just need to calculate the other side

OpenStudy (julyahx1):

its 5

OpenStudy (sooobored):

we isolate x on one side by multiplying 7.5 to both sides the 7.5 on the left side cancels out

OpenStudy (sooobored):

yes

OpenStudy (julyahx1):

omg i was like thinking 5 even before e started the problem lmao

OpenStudy (julyahx1):

like for the answer

OpenStudy (sooobored):

guessing doesnt help

OpenStudy (sooobored):

well, only educated guesses, but i highly doubt it was

OpenStudy (sooobored):

any questions?

OpenStudy (julyahx1):

but it was still right. and it was. i wasn't completely just guessing. i was thinking 5 because 4.5 is closest to 5

OpenStudy (julyahx1):

and every other number on that side was closest to hundreths place

OpenStudy (sooobored):

ok, it was a slight educated guess

OpenStudy (sooobored):

by looking at the magnitutde of the numbers

OpenStudy (julyahx1):

well i guess lol

OpenStudy (sooobored):

good job

OpenStudy (julyahx1):

thanks for ur help

OpenStudy (julyahx1):

good night

OpenStudy (sooobored):

now you should get a 100 on your next quiz, right?

OpenStudy (julyahx1):

thats what I'm hoping for

OpenStudy (sooobored):

good, night then

OpenStudy (julyahx1):

now gotta get some zzzzz

OpenStudy (julyahx1):

night

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