You apply a force to a steering wheel of 1.520 x 10^2 N at an angle of 23.20 degrees relative to the radial line. If the steering wheel has a diameter of 78.25 cm and rotates at the center of the wheel, what is the torque produced?

118.9 N·m

23.43 N·m

46.86 N·m

59.47 N·m
@3mar

Question

You apply a force to a steering wheel of 1.520 x 10^2 N at an angle of 23.20 degrees relative to the radial line. If the steering wheel has a diameter of 78.25 cm and rotates at the center of the wheel, what is the torque produced?
	
118.9 N·m
 	
23.43 N·m
 	
46.86 N·m
 	
59.47 N·m
@3mar

18jonea · Answer

could you set the problem up and i solve:?

3mar · Answer

Of course.
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18jonea · Answer

so what would  the equation be?

18jonea · Answer

@3mar

3mar · Answer

1 min

18jonea · Answer

ok

3mar · Answer

Firstly you have to solve this force F and have its normal (vertical) component to have a torque about the axis of the wheel...

18jonea · Answer

so what would i do im dorry just confused

18jonea · Answer

152 times 23 degrees?

3mar · Answer

No. it would be like that!!
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