Question

dos

Answer 1

anyone?

Answer 2

the denominator cannot be equal to zero
if you just look at the denominator and solve for x, then the solutions for x are x-asymptotes

Answer 3

so, it would be "B"?? @sooobored

Answer 4

no idea, didnt closely look at teh problem

Answer 5

oh well could you maybe confirm for me and take a look ? @sooobored

Answer 6

@calculusxy @steve816 @Directrix @mathmate @Nnesha

Answer 7

well close, what i explained was very very general method

there also exists something called the removable discontinuity,

basically x is an asymptote, but it get cancelled out by factoring from the numerator

and if i remember correctly, removable discontinuity are not asymptotes

factor the other part of the denominator and you should get the answer

Answer 8

@sooobored ohh it is D. No?

Answer 9

thats the answer i would go with

B. doesnt make much sense, since i assume the graph would cross through the x axis and roots exist so

Answer 10

the x axis being a asymptote doesnt make that much sense