How do I solve to find the x and y intercepts? y = x2 + x − 6? x-intercepts: (3, 0) and (2, 0) y-intercept: (0, 6) x-intercepts: (3, 0) and (−2, 0) y-intercept: (0, −6) x-intercepts: (−3, 0) and (2, 0) y-intercept: (0, −6) x-intercepts: (−3, 0) and (2, 0) y-intercept: (0, 6)
May I help?
yes plz
Thanks a lot.
Do you want to know that algebraically or graphically?
it's graph
As you wish. Could you plot this function and show me how does it look like?
This is the entire question hold on.What are the x- and y-intercepts of the graph of y = x^2 + x − 6? x-intercepts: (3, 0) and (2, 0) y-intercept: (0, 6) x-intercepts: (3, 0) and (−2, 0) y-intercept: (0, −6) x-intercepts: (−3, 0) and (2, 0) y-intercept: (0, −6) x-intercepts: (−3, 0) and (2, 0) y-intercept: (0, 6) Litterally there is nothing else.
I know, Ms! If you don't mind I need you to graph such equation on the grid! |dw:1478793887150:dw|
oh my bad
No problem, sister. Can you plot it?
Idk how...
No and yes in a way it wants me to find what the intercepts are from the equation y= x^2+x-6
For y-intercept: it is logic that x is equal to zero, then put x=0 and tell what y is!
-6 I got that
idk how to get x
It's one of the two middle choice answers B or C idk which. Since I can't figure out how to get x when there are two x's
-6 I got that \[\Huge\color{MediumBlue }\checkmark\] Yes, that is correct for Y. The same udea is for X. Let y=0 and let me know what you got!
I could only get this and i don't think it's right... \[6=x^2+x\]
can you take x as a common factor from the right-hand side?
would it become 1 or 2?
Can you share your works/steps, please?
6= x^2+x 6= x^2+x -1 -1 5= x^2?
To get the x intercept put y=0 To get the y intercept put x=0
To get x-values: form a full quadratic equation. |dw:1478795602489:dw|
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