Question

http://prntscr.com/d65fpe

Answer 1

@jhonyy9

Answer 2

inverse of a function

let f(x)=ax+b
let y=f(x)

y=ax+b

you want to rearrange for x

y=ax+b
y-b=ax
(y-b)/a=x

now you will swap the variable

(x-b)/a=y
and now you will let y=f^-1(x)

(x-b)/a=f^-1(x)

can you use these steps to solve your question

Answer 3

very nice work @amorfide - really understandably GREAT !!!

Answer 4

the idea is to make it equal to x

so if i had

f(x)=4x+9
to get to x I would subtract 9 from a variable then divide that answer by 4 so the inverse would be

f^-1(x)=(x-9)/4

Answer 5

so you can use the same logic for your question

Answer 6

ana please try using what ve wrote above @amorfide

Answer 7

here is the site where you can leaning again easy the steps

Answer 8

http://www.mathsisfun.com/sets/function-inverse.html

Answer 9

\[y=5x-10 \]
\[y-10=5x\]
\[(y-10)/5=x\]
\[(x-10)/5=4\]
(x-10/5=f^2 ( ) <<< dont know what to do from here or if i even got this right

Answer 10

@amorfide

Answer 11

@jhonyy9

Answer 12

why -10 when the function is f(x) = 5x-10 so y = 5x-10 so the first step will be
y+10 = 5x

yes ?

Answer 13

ok

Answer 14

i got 1.4

Answer 15

c

Answer 16

step by step please

Answer 17

have no time

Answer 18

y+10
----- = ?
5

Answer 19

yes you are right with 1,4 bc. will be (-3+10)/5 = 7/5 = 1,4

Answer 20

thanks

Answer 21

yw.

was my pleasure

good luck

bye bye