hello, I need to solve this task find values of a when function is Increasing from -∞ to +∞ (real numbers plurality) function is: y=f(x)=1/2*x^3+a*x^2+x-7 firstible i found derivative f'(x)=3/2*x^2+2ax+1 when I showed what disertive has to be bigger than 0 3/2*x^2+2ax+1>0 how to continue or I'm doing it wrong ? please help me as soon as possible.
\[\frac{ 3 }{ 2 }*x ^{2}+2ax+1>0\]
this inequality has to be true for every single real number x
but only for some number a
so the first thing i can think of is to try some particlar value of a and see what we get
but how to write answer ? i need to find values and write them but I do not know how
dont panic,I dont either but Im trying to figure it out
the x^2 term is always positive or 0, so the 2ax+1 should always be positive
so a is greater than -1/(2x) right?
I think thats the answer
it didnt say a has to be a constant, did it? so basically does the question allow a to depend on x or not?
or do you just need specific examples of a rather than a general fomula
but a is from real numbers plurality, so if a=-100 3/2∗x2+2(-100)x+1>0
idk i do not understand this task i only know what disertive has to be bigger than 0 but how to write answer do no know
@steve816 can you continue doing and/or check my work? Im on another question
First of all @raimondas. it is derivative, not disertive.
The function will be increasing if derivative is greater than 0, so just set the derivative equal to 0 and solve the equation.
oh sorry im thinking about that task and do not check my english :/
i set derivative and equaled it to 0 already but problem is that i can't solve it
firstible i found derivative f'(x)=3/2*x^2+2ax+1 when I showed what disertive has to be bigger than 0 3/2*x^2+2ax+1>0 or there are any mistakes ?
but I need to find values of a when function will increase but not x so there is my problem...
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