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OpenStudy (gallanth):
OpenStudy (matthew120):
@callielovesyhuu
OpenStudy (matthew120):
|dw:1478985310985:dw|
OpenStudy (matthew120):
thats a 90 right
OpenStudy (gallanth):
yes
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OpenStudy (matthew120):
4/5
OpenStudy (matthew120):
those are 1 of the answers right ?
OpenStudy (gallanth):
yes it was. thank you!!!!
OpenStudy (matthew120):
np
OpenStudy (matthew120):
is that it ? ?
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OpenStudy (gallanth):
i have more i may ask
OpenStudy (matthew120):
kk
OpenStudy (gallanth):
Find the measure of angle D. Round to the nearest tenth.
OpenStudy (mathmate):
|dw:1478985909600:dw|
OpenStudy (mathmate):
Use Pythagorean theorem to calculate HF,
|dw:1478985964267:dw|
\(x^2=sqrt(sqrt(8)^2+sqrt(8)^2)=8+8=16\)
so x=4.
Again use Pythagorean theorem to calculate y
\(y^2=sqrt(3^2+x^2)=sqrt(3^2+4^2)=sqrt(25)=5\)
BUT
\(cos \angle FEH =adjacent/hypotenuse = 3/y=? \) (answer is NOT 4/5).
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OpenStudy (gallanth):
whats the answer then
OpenStudy (gallanth):
my choices are
A. 3/4
B. 4/5
C. Square root of 8/3
D. 4/3
OpenStudy (mathmate):
Enough hint for the first problem.
You will find the answer if you had taken the time to read what I wrote.
Hint for the second problem (which you should have made a new post).
use the rule of cosines.
OpenStudy (mathmate):
Sorry, my bad. The first problem was for cosine of angle FHE, so 4/5 is correct.