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What is the vertex for the graph of y-2=-(x+3)^2 A (-3,2) B (-2,3) C (2,-3) D (3,-2)
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the vertex form of this type of equation is y = a(x - b)^2 + c where (b,c) is the vertex
So rearrange your equation to the above form and you'll get the answer.
Hint: you just have to add + 2 to both sides of your equation
So B?
No what is the value of c when you have added the 2?
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Ha yeah its A, thanks!
y - 2 + 2 = -(x + 3)^2 + 2
yw
y = a(x - b)^2 + c y = -(x + 3)^2 + 2 -b = 3 so b = -3 and c = 2
(b , c) = (-3, 2)
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