Question

word problem attached. I got 5 for the answer and it is wrong

Answer 1

So was there even more wind while going there? So confusing...

Answer 2

Let v be the velocity with no winds at all
the v+5 will be the velocity with the wind and v-5 the velocity against the wind

Answer 3

Then find the time in either way and the difference is 10 then solve for v

Answer 4

You need to start by choosing some letters to represent your unknown. You could, for example, represent the speed of the aircraft when there is no wind by x.

Remember that in a problem like this one, you're dealing with 1) time, 2) speed, and 3) distance.

distance = (speed) * (time)

Answer 5

\[
\frac{4071}{v-5}\]
is the time against the wind

Answer 6

What is it with the wind

Answer 7

I got -10r^2=-250
Divide by 10 and you get r^2=25
25 is a perfect square of 5...

r^2 = r squared

Answer 8

Where did you get that?

Answer 9

Are you following my hints before?

Answer 10

The time against the wind
is
\[
\frac{4071}{v+5}\]

Answer 11

Here is the equation
\[
\frac{4071}{v-5}=\frac{4071}{v+5}+10
\]
Solve for v

Answer 12

The picture I posted is the way she wants us to set it up

Answer 13

That is exactly (almost) what I did

Answer 14

When I solved completely I got the answer 5

Answer 15

v=5 will make the velocity against the wind zero, which means the plane will stand still

Answer 16

\[
\frac{4071}{v-5}=\frac{4071}{v+5}=-\frac{10 \left(v^2-4096\right)}{(v-5) (v+5)}\]

Answer 17

\[
v=\sqrt{4096}=64
\]