for the reaction shown here 4PH3(g)6H2(g)+P4(g) the equilibrium concentrations were found to be [PH3] = .250 M [H2]= .510 M [P4]= .750 M what is the equilibrium constant for this reaction?

Question

for the reaction shown here  
4PH3(g)<->6H2(g)+P4(g)

the equilibrium concentrations were found to be 
[PH3] = .250 M [H2]= .510 M [P4]= .750 M
what is the equilibrium constant for this reaction?

yerssonc · Answer

Product/reactant = 

[H2]^ x [P4] / [P X H3]^4 = 

[.750] x [.510]^6 / [.250]^4 =

3.38