Question

Use the quadratic formula to solve the equation
-4x^2-3x+2=0
Please explain if you can
Thanks

Answer 1

-4x^2-3x+2=0
a=-4
b=-3
c=2
x=[-b +-sqrt(b^2 - 4*a*c)] / 2a
x= [--3 +-sqrt(-3^2 -(4*-4*2))]/2*-4
x = [3 +-sqrt(9 -(-32)] / -8
x = [3 +- sqrt(41)]/ -8

Answer 2

x = (3 + sqrt(41))/ -8
x = (3 - sqrt(41))/ -8

Answer 3

Does that help Mason?

Answer 4

Yes kind of thank you for explaining

Answer 5

u r welcome