A ball's mass is 1.50 kilograms, and it leaves the racket with a horizontal speed of, say, 90 mph. Find the average force on the tennis ball as it is served.
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OpenStudy (girlstudy):
@tshimp0629
OpenStudy (tshimp0629):
ohhhhhhhhh eh hahaha ummmmmm 1 sec
OpenStudy (tshimp0629):
ya no i dont remember this stuff
OpenStudy (girlstudy):
kk thanks tho
OpenStudy (blee1000):
Im only in 6th grade and I think the average force is 60
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OpenStudy (girlstudy):
@Ms-Brains
OpenStudy (blee1000):
im sorry
OpenStudy (irishboy123):
you need more info
bum question :-(
OpenStudy (girlstudy):
@IrishBoy123 Thats all the info that was given. Is it impossible to do this question?
OpenStudy (irishboy123):
yes
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OpenStudy (girlstudy):
@IrishBoy123 :(
OpenStudy (irishboy123):
\(F = ma = m \dfrac{\Delta v}{\Delta t}\)
\(F_{average} \cdot \Delta t= m \Delta v\)
you have the \(m\) and you can assume that \(\Delta v = 90mph\)
if you knew \(\Delta t\), you could also guess \(F_{average}\)
OpenStudy (girlstudy):
@IrishBoy123 Can you substitute T for 9.81?
OpenStudy (girlstudy):
@IrishBoy123 Would it make sense to just multiply mass and acceleration only?
OpenStudy (irishboy123):
here, all you can do is calculate the final momentum of the ball.
you have no idea how that changed with respect to time.
and Newton's 2nd Law is that Force = rate of change of momentum wrt time.
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