Question

A wire that is 0.20 meters long is moved perpendicularly through a magnetic field of strength 0.45 newtons/amperes·meter at a speed of 10.0 meters/second. What is the emf produced?

Answer 1

this is a good start

in the drawing, the B-field should be everywhere.

does this get you started?!?!

Answer 2

it's not a circuit, so you get no current apart from the initial build-up of charge on either end of the wire, which is where the energy is stored.

so, some kinda thermal current as the charges move due to the B field.

there's a load of symmetry here but not sure how to derive the bold assertion that \(\mathcal{E} = v B L \).

but the basis is Lorentz Force Law: \( \mathbf{F} = q (\mathbf{v} \times \mathbf{B} ) \)