Question

@Whitemonsterbunny17

Answer 1

@Whitemonsterbunny17

Answer 2

@SolomonZelman can help :D

Answer 3

Anyone help because this is the hardest thing I have done in my 10 years of school

Answer 4

You are basically given that
\(\color{black}{N_0=29~}\) grams
\(\color{black}{k=0.1359~}\) (no units)

Answer 5

what function do you then have? (rewrite with this given infor)

Answer 6

N=29e^-0.1359t

Answer 7

Yes, good:)

Answer 8

Half life of a substance is the time that is required for this substance to reduce to half it's initial value. (i.e. After what time, will the amount substance be twice less?)

Your current value is: \(\color{black}{N=29e^{-0.1359t} }\).
At \(\color{black}{t=0 }\) you have \(\color{black}{N=29=N_0 }\).
At what time would you get \(\color{black}{N=\frac{1}{2}N_0=14.5 }\) ?

Answer 9

At what time t, would your N(t) be half of the initial value (i.e. 14.5)?
\(\color{black}{N=29e^{-0.1359t} }\)
\(\color{black}{\color{blue}{14.5}=29e^{-0.1359t} }\)

then solve for t.

Answer 10

546.947557 That was I got

Answer 11

You can solve it
1. Using logarithms
2. by graphing (the function \(\color{black}{\small N(t)=29e^{\normalsize -0.1359t} }\) and the line \(\color{black}{\small N=14.5 }\))

Answer 12

I don't think your solution s correct.

Answer 13

have you learned logarithms?

Answer 14

NOPE

Answer 15

So will do it by graphing.

Answer 16

You have a function \(\color{black}{N(t)=29e^{-0.1359t} }\), and you want to find the value of \(t\) for which \(\color{black}{N=14.5}\). So, basically, (in your case N is y, and t is x ;; i.e. you are graphing N versus t), you need to graph these two and find the \(t\) (or x) coordinate of the intersection.

Answer 17

OMG I am so Lost

Answer 18

@ganeshie8 May I get some help?

Answer 19

is it 5.1 days?