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Physics 21 Online
OpenStudy (anwar1098):

I need help with an equation

OpenStudy (anwar1098):

F = kx k = ?

OpenStudy (frostbite):

I guess F is the force and x is an displacement from a reference point? In that case we got that k is a force constant.

OpenStudy (anwar1098):

Yes

OpenStudy (frostbite):

So what is it exactly you want help to do with this equation?

OpenStudy (anwar1098):

If the equation if F = kx what will it be it is K =

OpenStudy (anwar1098):

I think it would be f/x but i dont know if it correct

OpenStudy (frostbite):

That is correct. :) \[\Large F=k \times x \] Divide on both sides of the equation with \(x\) and we get: \[\Large k=\frac{ F }{ x }\]

OpenStudy (anwar1098):

thanks for the help but if you dont mind can you help me with another one

OpenStudy (frostbite):

Sure. Usually openstudy runs a policy of 1 question / post. But lets just take a look at the question in this post :)

OpenStudy (anwar1098):

F = Gm^2/r^2 G = ? for this i think it is Fm^2/r^2

OpenStudy (frostbite):

You meant: \[\Large F=\frac{ G \times m^2 }{ r^2 }\] ?

OpenStudy (anwar1098):

yes that is it and it figured out the answer thanks for the help

OpenStudy (frostbite):

Good good. So you saw that you need to flip fraction? G=Fr^2/m^2

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