Mathematics
18 Online
OpenStudy (itrymath):
please help
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OpenStudy (itrymath):
OpenStudy (itrymath):
@mathmale
OpenStudy (itrymath):
i think its B
OpenStudy (mathmale):
This problem is all about proportionality. What is the ratio of side ML to side DC?
Answer with a numeric rational fraction.
OpenStudy (mathmale):
ML
--- = ?
DC
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OpenStudy (itrymath):
its C
OpenStudy (itrymath):
i did the math
OpenStudy (mathmale):
Let's go thru the math, please. I want to know (and want you to know) where the proper answer comes from.
OpenStudy (itrymath):
I did the math lol
OpenStudy (mathmale):
What is that ratio?
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OpenStudy (itrymath):
\[\frac{ 2 }{ x } \frac{ 8 }{ 56 }\]
OpenStudy (itrymath):
cross multiply
OpenStudy (mathmale):
you can do that if you'd first write an = sign between your two fractions.
OpenStudy (itrymath):
x=14 ... i forgot sorry
OpenStudy (itrymath):
then \[\frac{ 9 }{ x } \frac{ 2 }{ 14 }\]
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OpenStudy (itrymath):
= sign in between them
OpenStudy (itrymath):
then cross multiply
OpenStudy (itrymath):
you get x=63
OpenStudy (mathmale):
Must use = sign between the fractions:
\[\frac{ 2 }{ x } =\frac{ 8 }{ 56 }\]
OpenStudy (itrymath):
then subtract 14 from 63
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OpenStudy (itrymath):
and you get 49
OpenStudy (mathmale):
Then 112=8x, and so x=?
OpenStudy (itrymath):
you divide
OpenStudy (mathmale):
Yes. Divide now, please.
OpenStudy (itrymath):
which gives 14
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OpenStudy (itrymath):
then 63-14=49 <------answer
OpenStudy (mathmale):
Yes. So, you have found the length of AB.
But you're supposed to find the length of AF.
OpenStudy (itrymath):
OOOOOOOOoomg
OpenStudy (mathmale):
Hello!
This problem is all about proportionality. The 2 figures are similar (but not coincident).
OpenStudy (itrymath):
wait so it is 49 inch
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OpenStudy (itrymath):
AF is 49
OpenStudy (triciaal):
wow correct
OpenStudy (mathmale):
Hold it. ItryMath: You have the same problem posted twice. Why?
OpenStudy (itrymath):
i dont think do
OpenStudy (triciaal):
do you mind if I show you the shorter version of the same thing?
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OpenStudy (itrymath):
sure
OpenStudy (triciaal):
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