AM I RIGHT HERE? CALC.
please lmk anyone!
?
please repost the graph not very clear
@triciaal sorry, here is the new one
@mathmate @triciaal @Loser66
it posted correctly can see everything now
@mathmale
not the solution but B is a parabola the derivative would be a straight line
@sshayer do you think A or C?
@mathmale
sorry should be @mathmate thanks @SolomonZelman
The derivative of the curve \(f(x)\), as we know by its limit definition, is the instantaneous slope of \(f(x)\) at any point x, and it is given by \(f'(x)\). So, if you see at \(x=\alpha\) that \(f_1(x)\) is increasing and \(f_2(\alpha)<0\), then \(f_2(x)\ne f_1'(x)\)
Alternatively, (the other way around) if at \(x=\alpha\), you have a decreasing \(f_1(x)\), and \(f_1(\alpha)>0\), then again \(f_1'(x)\ne f_2(x)\).
I am just going by definition that if a function is decreasing at a point, the slope (or the derivative) at this point should be negative. Or, if a function is increasing, the slope (or the derivative) at this point should be positive.
Look at x=0 carefully.
The slope of B is positive, but A<0. So A\(\ne\)B'.
Are you following with me? (If you lose me let me know.)
Looks like actually the function B can model the slope of function A.
(1) Before the first horizontal tangent, B is A is increasing but concave down. how can we tell this from the graph of A? Look at the tangent lines (before the turn), you will see their slope is positive, but this slope decreases. And so we have the correspondence from B. B is positive and decreases. The horizontal tangent points on curve A, correspond to values of B=0. etc...
Just examine curve A (at points x=δ), and see if B can (or cannot) fit as a slope at x=δ.
(for any x=δ you deem to examine to reach conclusion you see sufficient)
I never prohibited questions:)
@SolomonZelman thank you! i did all that and still ended up with A... is that correct??
no
help someone please
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