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Calculus1 15 Online
OpenStudy (avrii):

what is the period in seconds of a simple pendulum of length 3 meters? use the gravitational constant g = 9.8 m/s^2 and round your answer to two decimal places.

OpenStudy (mathmale):

Do you know a formula from physics for the period of a pendulum of given length? If not, please google "period of a pendulum." You'll find the formula that way.

OpenStudy (sshayer):

\[T=2 \pi \sqrt{\frac{ l }{ g }}\] l=3 meter. g=9.8 m/s^2 find T

OpenStudy (avrii):

so the answer would be 3.48 ?

OpenStudy (sshayer):

correct.

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