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what is the period in seconds of a simple pendulum of length 3 meters? use the gravitational constant g = 9.8 m/s^2 and round your answer to two decimal places.
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Do you know a formula from physics for the period of a pendulum of given length? If not, please google "period of a pendulum." You'll find the formula that way.
\[T=2 \pi \sqrt{\frac{ l }{ g }}\] l=3 meter. g=9.8 m/s^2 find T
so the answer would be 3.48 ?
correct.
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