Question

what is the period in seconds of a simple pendulum of length 3 meters? use the gravitational constant g = 9.8 m/s^2 and round your answer to two decimal places.

Answer 1

Do you know a formula from physics for the period of a pendulum of given length? If not, please google "period of a pendulum." You'll find the formula that way.

Answer 2

\[T=2 \pi \sqrt{\frac{ l }{ g }}\]
l=3 meter.
g=9.8 m/s^2
find T

Answer 3

so the answer would be 3.48 ?

Answer 4

correct.