I need help with solving these two 2 problems

Given that log_a (2) = 0.301, log_ a (5) = 0.699, and log _a ( 6 ) = 0.778

find log_a(4)

and log_a(1/6)

I don’t understand how you are suppose to find the answer using the change of base formula

Question

I need help with solving these two 2 problems

Given that log_a (2) = 0.301, log_ a (5) = 0.699, and log _a ( 6 ) = 0.778

find log_a(4)

and log_a(1/6)

I don’t understand how you are suppose to find the answer using the change of base formula

sam_pi · Answer

do you have any explanations or suggestions on how to begin to solve them?

fourier · Answer

$$\log_a 4 = \log_a 2^2 = 2\times \log_a 2 = ?$$

fourier · Answer

I have used the property
$$\log_a x^n = n\times \log_a x$$