A sandbag was thrown downward from a building. The function f(t) = -16t2 - 32t + 128 shows the height f(t), in feet, of the sandbag after t seconds. Part A: Factor the function f(t) and use the factors to interpret the meaning of the x-intercept of the function. (4 points) Part B: Complete the square of the expression for f(x) to determine the vertex of the graph of f(x). Would this be a maximum or minimum on the graph? (4 points) Part C: Use your answer in part B to determine the axis of symmetry for f(x)? (2 points)
yes def!
\[f(t)=-16t ^{2}-32t+128\]
I cant the policy says dont give direct answers without any working becuase thats cheating
\[-16(t ^{2}+2t-8)\]
\[-16(t +5)(t-3)\]
Yeah i get that part...
so f=0 when t=-5 or t=3, so the sandbags will land either "-5 seconds" later or 3 seconds later
obviously you want to throw out the negative answer
yeah the negative needs to go
I hate part B, becuase nobody complete square after they learn calculus, but I guess you can use calculus here
i never like these questions!
*cant
okay if you need to skip B we can go to C
I''ll just give you the answer by differentiating the function, you can complete the squares on your own and see if your answer matches mine
df/dt=-32t-32=0
so t=-1
and f=-16+32+128=144
so vertex is (-1,144)
and its clearly a max, since if the leading coeff is negative, the parabola opens downwards
just as a sanity check
d^2f/dt^2=-32,which is negative, and hence vertex is a maximum value
ok
symmetry is about t=-1
Yeah ik my mom just came in... its past my bedtime.. i gtg
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