Question

please help c:

A multi nominal experiment with k = 4 cells and n = 300 produced the data shown in the following table.

Do these data provide sufficient evidence to contradict the null hypothesis that P1= 0.20, 02 = 0.20, p3=0.30, and p4 = 0.30, test using Alpha = 0.05

Answer 1

@jim_thompson5910

Answer 2

I was wondering if this was asking me to do ANOVA, to see if at least one of the means was different. But is it the same as the other question I asked? Where the expected is 300/ (the p values) = expected value?

Answer 3

this is another `chi-square goodness of fit` type of problem

Answer 4

the claim here is...

P1 = 0.2
P2 = 0.2
P3 = 0.3
P4 = 0.3

ie the first probability is 0.2, the second is 0.2, the third is 0.3 and the fourth is 0.3

Answer 5

Translation: the claim is that if you randomly pick out a ball from any one cell, then the chances of picking a ball from cell1 is 20% since 0.2 = 20%

Picking a ball from cell 2 is also a 20% chance
cell 3 has a chance of 30%
cell 4 has a chance of 30%

this is assuming the claim is true

Answer 6

if we have 300 balls total and 20% of them should be in cell1, then how many should be in cell1?

Answer 7

ahh, I seem to have a hard time trying to chi square goodness fit problems.. so it would be:

Answer 8

how are you getting that?

Answer 9

you would do n*p

n = number of items
p = probability of landing in certain cell

so for the first cell, you would expect 60 since

n*p = 300*0.2 = 60