Question

what is the solution set for 7x^(-2)+26x^(-1)=8

Answer 1

May I help?

Answer 2

Multiply each term by x^2

Answer 3

Is that your equation?
\[\large 7x^{-2}+26x^{-1}=8\]
\[\large \frac{ 7 }{ x^2} +\frac{ 26 }{x} =8\]

Answer 4

@3mar Yes, can you please help me solve this?

Answer 5

That is with my pleasure!

What about multiplying both sides by \(x^2\)?

Answer 6

@3mar Would cross out the X under the 26 too?
7+26x=8x^2
or would it still be
7+26x^2/x=8x^2

Answer 7

\[\Huge \color{CadetBlue }{7+26x=8x^2 }\]
That is very good!

You are Awesome!

Answer 8

Can you put this equation in the standard form?