Three consecutive odd integers have a sum of
45. Find the integers.

Question

Three consecutive odd integers have a sum of 
45. Find the integers.

ebonyserrano · Answer

i think it might be 15,16, and 17

derricklewis · Answer

It is 15,16,17 plzz give me a medal

mrnood · Answer

16 is not odd
they do not add up to 45 

apart from that - you deserve a medal

mrnood · Answer

@Ebonyserrano 
if the middle of the 3 numbers is n (and is ODD)

how would oyu write an expression for the NEXT ODD number??

holsteremission · Answer

What was wrong with the other two times you posted this question? Both questions got answered. Seems to me you're not actually willing to do the work.

derricklewis · Answer

X+X+2+X+4=45
3X+6=45
3X=45-6
3X=39

derricklewis · Answer

hOPE I HELP
ED

mrnood · Answer

@derricklewis 
so how did you help by confirming his WRONG answer (and demanding a medal?)

ebonyserrano · Answer

@Will.H

will.h · Answer

Lol MrNood

will.h · Answer

Anyways. You'll need to make an expression

will.h · Answer

X + (x + 2) + (x + 4) = 45 
Solve for x 1st 
3x + 6 = 45 
3x = 39
X = 13 

Now substitute that in the expression above
The 1st integer would be 13 
The 2nd would be 15 
The 3rd would be 17 

Let's see it they add up to 45
13 + 15 + 17 = 45 
45 = 45 
Therefore the assumption was confirmed

will.h · Answer

Make sense?

ebonyserrano · Answer

yea thank you