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Now these are fractions. :/ http://prntscr.com/dbueyv
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\[\large\rm \sqrt{\frac ab}=\frac{\sqrt a}{\sqrt b}\]So... same type of idea for this problem. We'll need both squares roots, the one in the top as well as the one in the bottom, to be nice pretty numbers.
so you're saying that \[\sqrt{\frac{ 9 }{ 16 }}\]is a rational number?
If I gave you this,\[\large\rm \sqrt{\frac{25}{36}}\quad=\quad \frac{\sqrt{25}}{\sqrt{36}}\]Both values under the root are perfet squares, ya?
because 9 has a perfect square along with 16
yah
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Mmmm yes, good.
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