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The problem in the comments was generated from problems similar on http://saab.org
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72 cm^2 is area of this rhombus - is this answer right ? than yes ,i will write the way how i ve solved it without paper and pen - ty. this is very interesting exercise
No, it is not 72 cm^2
I am thoughts so far: angle NMP and NPM are known and are same, so PMN can be calculated, since NO bisects PMN, the angle MNO is known. Take the tan of MNO gives you OM/ON, OM is 6cm by construction, so ON is known
the area is 4 time the area of triangle OMN, which is 2*OM*ON
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|dw:1480268854918:dw|
|dw:1480269019207:dw| AM = MO = OP = PB = 6 cm
|dw:1480269055518:dw|
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