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Implicit Differentiation?
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\[\ln(xy) =e ^{x+y}\]
The question is asking for dy/dx. I have this so far, but I can't figure out how to solve for y'.\[\frac{ y+xy' }{ xy } = e^{x+y}(1+y')\]
\[\Rightarrow\frac{ y}{xy}+\frac{xy' }{ xy } = e^{x+y}+e^{x+y}y'\]
You might try the Implicit Function Theorem, if you know it: So \(f(x,y) = \ln(xy) - e ^{x+y}\) and then \(\dfrac{dy}{dx} = - \dfrac{f_x}{f_y}\)
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