Solve the system of equations by substitution. What is the solution for x? 2x + y = 1 4x + 2y = −2 x = 0 x = 2 There is no x value, as there is no solution. - This one x can be any value, as there is an infinite number of solutions.
hint: multiply the first equation by 2
ok thanks
let me know if you get stuck
i got 2x+y=2, so x would be 2? right
nope
i substituted what i needed to?
what is 2x * 2?
4x
good, what is y * 2?
isnt it 2y
good so that gives us: 4x + 2y = 2 4x + 2y = -2
now subtract the two equations let me know what you get
x= 1/4 and y=-3/2
??????
no?
what is 4x - 4x?
0 of course
good now what is 2y - 2y?
0
good what about 2 - (-2)?
4?
good! so that gives us: 0 = -4 which has no solution
ohh ok thank you so much i did consider that but wasnt sure!
so its c!
Vocaloid has just given you the elimination method. Here is another method but it's by substitution (which is also what the question wants) 2x + y = 1 4x + 2y = −2 Rearrange the first equation so that y is on one side: y=1-2x That is the value for y, so you can plug that in for your second equation: 4x + 2(1-2x) = -2 Expand: 4x+2-4x=-2 Simplify: 2=-2 Obviously this is incorrect so the answer is C.
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