Write the equation in vertex form for the parabola with vertex (0, 4) and focus (0, 6).

Question

3mar · Answer

So at the beginning, it is a vertical parabola!
|dw:1480277674640:dw|


Can you create its equation?

samferguson · Answer

I am not sure how to create the equation at all

3mar · Answer

so Where are you stuck?

samferguson · Answer

I don't know where to start. Please give answer

3mar · Answer

It is not helpful for you to be given the answers without understanding how they are figured out!

Step by step, I will give you through the answer!

samferguson · Answer

ok 
lets start

3mar · Answer

What is the general equation of the vertical parabola?

samferguson · Answer

$$y=ax ^{2}+b$$

samferguson · Answer

not sure if thats right

3mar · Answer

You mean that?

$$\LARGE y=ax^2+bx+c$$
or 
$$\LARGE y=a(x+b)^2+c$$
which one are you familiar with?

3mar · Answer

@samferguson
Do you follow?

3mar · Answer

Let me know where you are back!

loser66 · Answer

When they give you the focus, then use it. (0, p) is a focus, so, $(x-h)^2=4p(y-k)$ when (h, k) is vertex.