Question

1. Cross one parent that is heterozygous for both beak color and feather color with a parent that is homozygous for both recessive

Answer 1

Answer the questions below. When you are finished, submit this assignment to your teacher by the due date for full credit.
For all questions, assume that you have genes for beak color, tail-feather length, and feather color all linked (located) on the same chromosome, but you don't know the order of the genes on the chromosome or the distance between them. The alleles for these genes are
beak color: Y for yellow beak (YY and Yy) and y for black beak (yy)
tail-feather length: L for long tail (LL and Ll) and l for short tail (ll)
feather color: B for blue feathers (BB and Bb) and b for white feathers (bb)
Part 1: Crossing Beak Color and Tail-Feather Length
Cross a YyLl (heterozygous parent with dominant traits) with yyll (homozygous parent with recessive traits). Look at the number of phenotypes of the F1 generation:
YyLl: 400
Yyll: 100
yyLl: 100
yyll: 400
(2 points

Answer 2

@Destroyer5 @563blackghost @518nad @Will.H

Answer 3

is this flvs?

Answer 4

i dont know what that is

Answer 5

is it online school

Answer 6

yes its K12

Answer 7

ok, do u know anything here?

Answer 8

not really

Answer 9

im not sure, i have done this but it was a long time ago i will try and rethink

Answer 10

do u know what a chromosome is?