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Mathematics 7 Online
OpenStudy (amy2012):

Problem attached

OpenStudy (daniyil_the_spy):

2 what

OpenStudy (amy2012):

OpenStudy (amy2012):

It is attached @Daniyil_the_spy

OpenStudy (daniyil_the_spy):

oh quick question how do you do the blue stuff

OpenStudy (daniyil_the_spy):

Amy2012

OpenStudy (mirving):

3mar

OpenStudy (daniyil_the_spy):

?

OpenStudy (amy2012):

@3mar

jhonyy9 (jhonyy9):

x^2 -5x +4 = (x-4)(x-1) f(x) =g(x) x 9 -17x +26 ---- - ----- = ------------ x-4 x-1 x^2 -5x +4 x(x-1) -9(x-4) -17x +26 -------------- = ----------- (x-4)(x-1) (x-4)(x-1) x^2 -x -9x +36 = -17x +26 x^2 -10x +36 = -17x +26 x^2 +7x +10 = 0 (x +5)(x+2) = 0 x+5=0 x_1 = -5 x+2=0 x_2= -2 x = -5 and -2 hope helped

OpenStudy (3mar):

I am sorry for late! I was not here! Steps: - equate the two functions to each other! - unify the denominator of f(x) (and it will be the same as the denominator of g(x) by the way) - for the same denominators, the numerators are equal. - form an equation of the two numerators and SOLVE for X....(you will get a quadratic one, solve for it by either factoring or using the quadratic formula..it is up to you) I think @jhonyy9 did it very well as it should be! Thanks for him! If you still need help, I am with you if you face any difficulties!

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