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My teacher went over this with us this morning, may someone help me again? :)
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i will <3 2 help u
ok go for it
d?
D
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No direct answers, please. :(
@triciaal, may you help me? :)
\[ 4^{-(y+1)}=64=4^3\] -(y+1)=3 ?
are you learning logs? or just exponents 64 can be expressed as 4^3 rules for exponents
\[\left( \frac{ 1 }{ 4 } \right)^{y+1}=\left(1* 4^{-1} \right)^{y+1}=\left\{ \left( 4 \right)^{-1} \right\}^{y+1}=4^{-(y+1)}\]
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Just exponents hahaha!! Tkhunny was using Logarithms earlier that's what confused me. :P
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