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Linear Algebra
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PLZ HELP! Graph y= –3x+4y= –3x+4 .
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I am assuming that you have to graph only one equation \(y = -3x+ 4\). To do that you have to first start with the y-intercept, which is 4. (Remember \(\color{red}{y = mx + b}\)). We graph the first point at (0, 4). The slope is -3 meaning to go down 3 units and to the right one. (Remember \(\frac{\text{rise}}{\text{run}}\)). The next point would be (1, 1) and if you continue that manner then you should get more points. Your line should look something like this:
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