What is the equation of the line that has a slope of 3 and goes through point (4, 7)?
equation form when the line passes through \((x_1,y_1)\) & has the slope m is \[(y-y_1)=m(x-x_1)\]
u can also use this method : slope intercept form\[y=mx+c\]where m=slope c=y-intercept
substitute (x,y)=(4,7) and m=3 into the eqn to find the value of c
so the equation could be 7=3*4+c
@jiteshmeghwal9 method is a bit faster..u can use the slope intercept form to double check ur answer..
yep,that's right.. @Theoneandonly
solve it to find the c.. 7=12+c 7-12=12-12+c c=-5
then form the eqn by substituting m=3 n c=-5 into y=mx+c
so the final answer is 7=3*4+(-5)
u do not need to put the value for x and y,when u want to form the eqn..
for example,\[y=3x-7\]
oh ok
okay..back to ur question.. now u hv the value of m=3 and c=-5.. substitute those values into y=mx+c to form the eqn
\[y=(3)x+(-5)\]
Therefore,ur eqn is y=3x-5
ok thank you! So my final answer is y=3x-5
yeap,that's right! ^
yw! (:
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