Help pls? Will award medal! What is the solution to x2 + 3x + 25 = 0?
Do you think the equation is factorable?
I'm not sure if you meant 2x instead of x2.
No.. and its x^2
x2 means \(x^2\)
Ah okay, thats what I originally thought, but I felt it was more basic. :P Sorry hehe
use wolframalpha.com and type in factor "your equation"
The solution is actually imaginary :)
Or no real solutions
So I'll have to use the -b+- sqrt equation right?
Yep, this to be exact \[x=\frac{-b \pm \sqrt{b^2-4ac}}{2a}\]
Where a=1, b=3, c=25
y = -b+- sqrt_/ b^2 - 4ac/2a y = -3 +- sqrt_/3^2 - 4*1*25 / 2*1 y = -3 +- sqrt_/ 9 - 4*25 / 2 y = -3 +- sqrt_/ 9-100 / 2 y = -3 +- sqrt/ -46 so like this?
-3 +/- sqrt (9 - 4*25) = -3 +/- sqrt (-91)
- oh all that divided by 2 !!!
are you familiar with imaginary numbers? sqrt(-1) = i ?
sooo I find the square root of -91 and then divide it by 2?
you divide it all by 2 -3 +/- sqrt91 i ------------ 2
oh ok
i is the symbol for sqrt (-1)
the roots consist of 2 complex numbers a complex number has a real and an imaginary part
we can write them as |dw:1480445438693:dw|
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