Question

Sarah needs to have a plumber come to her house and fix a leaky faucet in her 
bathroom. The plumber charges $50 to come to her home and an additional $30.75 
every hour he works on the job. Sarah only has $234.50 in her savings for the 
repair. What is the maximum amount of hours that Sarah can have the plumber work 
on her faucet?
A 9
B 7
C 6
D 8

Answer 1

@mathstudent55

Answer 2

234.50 = 50+30.75h

Answer 3

Explain?

Answer 4

One time charge of 50, plus 30.75 per every hour is equal to the max money Sarah has to pay with

Answer 5

How would I get h

Answer 6

h is just a variable for hours, solve for h

Answer 7

Or do you not know how?

Answer 8

Wait ill try

Answer 9

I got 6 :/

Answer 10

yup

Answer 11

Ty

Answer 12

6 is not just 6, but the number of hours

Answer 13

I know :)

Answer 14

Plumber cost: fixed $50 plus $30.75 per hour
If the plumber works h hours, the hourly fee will be 30.75h
The plumber cost, then, is

30.75h + 50

She has 234.50

The cost expression must be less than or equal to 234.50

\(30.75h + 50 \le 234.50\)

Solve for h.
Subtract 50 from both sides:

\(30.75h \le 184.50\)

Divide both sides by 30.75

\(h \le 6\)

Answer: she can hire the plumber for at most 6 hours.

Answer 15

Thank you both!!

Answer 16

You're welcome.