I will give medal and fan NEED HELP
I got part 1, 2, 4, i need help on part 3
Task 1 Part 1. Using the two functions listed below, insert numbers in place of the letters a, b, c, and d so that f(x) and g(x) are inverses. f(x)= x+a/b x+6/3 g(x)=cx−d 3x-6 Part 2. Show your work to prove that the inverse of f(x) is g(x). F(x) = x + 6/3 Y = x+6/3 3 x y = x + 6 3y-6=x X=3y-6 G(x)=3x-6 Part 3. Show your work to evaluate g(f(x)).
Well, first what are inverses?
I got all of that part but there pretty much wanting f(x) become or how it is the same as g(x)
They are making fx into gx or gx into fx right?
hold on
I get the idea of inverses just dont know how to put it in words
Okay. So now that you did the work, you need help explaining it?
I just need help on part 3 and the rest of task 2
part 3 on task 1
Okay so you know what g(f(x)) means right?
meaning that you need to combine those?
Well f(x) is a function, right? And so you are multiplying g by f(x). Am I right? *it's been awhile soooo
Hold on let me check
so would it be 3x-4?
Could you show how you did that real quick?
I got help from another person and he told me but I dont think it was the whole thing then never got back on
I try to find it real quick
ok
http://home.windstream.net/okrebs/page42.html This gave me an idea of how to do it
Oh! I found something: "Yes. Part 1 just asked you to put in real numbers so we used: f(x)=x+3/5 and g(x)=5x-3 Then part 2 asked you to show how f(x) was the inverse of g(x) and we did that by doing: x=f(x)+3/5 and got the inverse as 5x-3. And part 3 said to evaluate g(f(x)) which we did by putting f(x) in for the x of g(x) and showed that it comes out to = x which is what you'll always get if you're doing it right." -marissalovescats
So what I think that means is: \[g(f(x))\] \[g(f(x))=3(f(x))-6\]
so how did you get that?
I think it needs to be in a equation form
Because g(x) = 3x-6 so if x = f(x) then g(f(x))=3(f(x))-6 Compare \[g(x) = 3x-6\] and \[g(f(x))=3(f(x))-6\]
Oh okay so \[=3(x+6/3)-6\]
\[=3(x+2)-6\]
Yes thats it I now need help with task 2
just give me a sec
Task 2 numbers A-2 B-8 C-4 D-6
Are they asking for two type of sets of numbers?
I think they're just asking for two equations using a√x+b+c=d
By switching the numbers around?
So the first equation is \[2\sqrt{8+4+6}\]
Well why did you susbstitute x for the value that goes with b? I got \[2\sqrt{x+8}+4=6\]
arrgh I'm so sorry I have to go :(
oh ok
Join our real-time social learning platform and learn together with your friends!