Question

I need help with this please! I want someone to go through the steps with me, not tell me the answer. Thanks~! ^_^

Three Algebra 1 students are comparing how fast their social media posts have spread. Their results are shown in the following table.

1. Write an exponential function to represent the spread of Ben's social media post.

Answer 1

What about the last one?

Answer 2

For the question, I got:

\[f(x)= 2(3)^{x}\]

Answer 3

I got that one already, I just need to check some of these and I need help on some other ones.

Answer 4

Is what I got correct?

Answer 5

I am asking about the last question you said: I will be back?

Answer 6

Yea, I know. I just need to make sure that I have these right because I have to turn it in as an assignment so I wanted to make sure I did them good. It has 7 parts to the whole question but I was only able to do 3 so far.

Answer 7

You are correct, where x is the day number...ok?

Answer 8

Ok cool. how about this one:

2. Write an exponential function to represent the spread of Carter's social media post.

I got: \[f(x)= 10(2)^{x}\]
Is that right?

Answer 9

\[\Huge\color{Coral}\checkmark\]
I think you got it!

Answer 10

Wow! Nice! Ok, there's one more that I need to check and the rest I need help on if you're ok with that. ^_^

Answer 11

Can we start in new post, please?

Answer 12

Why???

Answer 13

@Hero Can you help me please?

Answer 14

@jigglypuff314 I need help please. Thanks! ^_^

Answer 15

because one question in one post!
These are the rules!

Answer 16

They are?

Answer 17

Well, it's the same question but it has 7 parts to it.

Answer 18

Ok
GO on for one more only, as it is a check

Answer 19

Alright. This is the other part: Using the functions for each student, predict how many shares each student's post will have received on Day 3 and then on Day 10. Justify your answers.

I got:

for Ben: \[f(3)= 2(3)^{3}\]\[f(3)= 2(27)\]\[f(3)= 54\]
\[f(10)= 2(3)^{10}\]\[f(10)= 2(59,049)\]\[f(10)= 118,098\]
\[\frac{ 118,098 - 54 }{ 10 - 3 }\]\[\frac{ 118,044 }{ 7 }\]
\[16,863.42\]

Answer 20

Can you rephrase your question?

Answer 21

For Carter:

\[f(3)= 10(2)^{3}\]\[f(3)= 10(8)\]\[f(3)= 80\]
\[f(10)= 10(2)^{10}\]\[f(10)= 10(1,024)\]\[f(10)= 10,240\]
\[\frac{ 10,240 - 80 }{ 10 - 3 }\]\[\frac{ 10,160 }{ 7 }\]\[1,451.42\]

Answer 22

Alright. Um how?

Answer 23

"Using the functions for each student, predict how many shares each student's post will have received on Day 3 and then on Day 10"

Answer 24

Don't they want to know how any shares Amber, Ben, and Carter have for their photos on day 3 and day 10? That's what I understood.

Answer 25

*many

Answer 26

Is that a little better?

Answer 27

Yes, I got it now.
So they want to know how is f(x) would be if x=3 and x=10
right?

Answer 28

Yea for all three students

Answer 29

That's what I understood from that question.

Answer 30

Ok.
So what you did so?

Answer 31

Well I already showed what I did to get Ben and Carter's amount of shares. And I'll show what I did to get Amber's.

Answer 32

For Amber:

\[f(3)= 3(4)^{3}\]\[f(3)= 3(64)\]\[f(3)= 192\]
\[f(10)= 3(4)^{10}\]\[f(10)= 3(1,048,576)\]\[f(10)= 3,145,728\]
\[\frac{ 3,145,728 - 192 }{ 10 - 3 }\]\[\frac{ 3,145,536 }{ 7 }\]\[449,362.28\]

Answer 33

Yea I did that for Carter.

Answer 34

Ok.
But why did you subtract f(10)-f(3).
It does not need that!
JUST " predict how many shares each student's post will have received on Day 3 and then on Day 10"

Answer 35

Hmm. Ok so what would that look like?

Answer 36

@TheSmartOne Is all of my work correct so far?

Answer 37

It looks like you did something is not required!

Answer 38

Yea? So I don't need to subtract?

Answer 39

@Ashleyisakitty Can you help out please? I'm trying to get as much help as I can. This one is a bit tricky. T_T

Answer 40

Yes, you don't need to !

Answer 41

So would I just add them or combine them like the other one we did that we had to combine the function?

Answer 42

I'm a bit confused on this part. T_T

Answer 43

NO NEED TO DO ANYTHING UNLESS FIND THE VALUES OF F(3) AND F(10)
why you insist to make it hard for you>>>>>>>>>>>>>>>>>>>>>>>>>>>>>

Answer 44

tag anyone to ask and be sure...No problem.

Answer 45

Ooooohhhhhh! So I just solve the functions themselves. Ok. xD I don't know why I do all this extra stuff. lol

Answer 46

Ask yourself, genius!

Answer 47

You search for troubles ;)

Answer 48

lololol

Answer 49

Bad habits! Bad bad bad habits XD lololol

Answer 50

I want to meet you!

Answer 51

Any more questions?